katara2 katara2

01-03-2017
Mathematics

contestada

solve for y (y+2)^2=2y^2+14y+28

Respuesta :

sdmatera sdmatera

01-03-2017

y=-6 and -4

y^2+4y+4=2y^2+14y+28
0=y^2+10y+24
0=(y+6)(y+4)
y=-6 y=-4

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