siyamhatim66 siyamhatim66
  • 03-11-2021
  • Mathematics
contestada

helpenejiriehdisnsjsos​

helpenejiriehdisnsjsos class=

Respuesta :

mathstudent55
mathstudent55 mathstudent55
  • 03-11-2021

Answer:

[tex] 2 + \sqrt{3} [/tex]

Step-by-step explanation:

[tex] \dfrac{1}{\sqrt{4} - \sqrt{3}} = [/tex]

[tex] = \dfrac{1}{2 - \sqrt{3}} [/tex]

[tex] = \dfrac{1}{2 - \sqrt{3}} \times \dfrac{2 + \sqrt{3}}{2 + \sqrt{3}} [/tex]

[tex] = \dfrac{2 + \sqrt{3}}{(2 - \sqrt{3})(2 + \sqrt{3})} [/tex]

[tex] = \dfrac{2 + \sqrt{3}}{4 - 3} [/tex]

[tex] = \dfrac{2 + \sqrt{3}}{1} [/tex]

[tex] = 2 + \sqrt{3} [/tex]

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