yuneek99 yuneek99
  • 02-09-2020
  • Computers and Technology
contestada

You have an array of integers: int myints[10]; and the address of the first integer is be4350. What is the address of myints[1]? myints[2]?

Respuesta :

tonb
tonb tonb
  • 02-09-2020

Answer:

&myints[1] == 0xbe4354

&myints[2] == 0xbe4358

Explanation:

Assuming that sizeof(int) == 4, add 4 bytes for every array element.

Answer Link

Otras preguntas

Two students try to move a heavy box. One pushes with the force of the 80N while the other pulls with a force of 40N in the same direction. What is the work don
prove that root 3 + root 7 is irrational​
(f) What do people do in picnics apart from eating?​
I need help ASAP!!People that now what there doing
Please I need help will get max points as many as
Ahmad Conan deposited 60 quarters, 53 dimes, 44 nickels, and 50 pennies into his checking account. The total of the checks he deposited equaled $17 less than tw
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!
Who can contact me to help me with the American literature 1800 exam on Monday?
1+-2/3--m where m=9/2
Solve for x Answer options: 4 5 8 3 2